20x-2x^2=-22

Solution for 20x-2x^2=-22 equation:

20x-2x^2=-22

We move all terms to the left:

20x-2x^2-(-22)=0

We add all the numbers together, and all the variables

-2x^2+20x+22=0

a = -2; b = 20; c = +22;
Δ = b2-4ac
Δ = 202-4·(-2)·22
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-24}{2*-2}=\frac{-44}{-4}
=+11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+24}{2*-2}=\frac{4}{-4}
=-1
$